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39 qldkoreanlife.com.au FRI. 22. JULY. 982 가로열쇠 1.남에게업신여김을받음 2.마음속으로괴로워하고애를태움 4.땅에두드려박는몽둥이 5.인간다운따뜻한맛 7.가을의금강산 9.채석강.내소사가있는부안군에있는반도 11.영화를만들기위하여쓴각본 13.역사적인유물이나자취가남아있는곳 15.몸집이작은종자의말 16.정치상의권세 17.각을뜬돼지의발 18.앞지르기 세로열쇠 1.연기가빠져나가도록만든구조물 3.나무가없는산 4.말을이리저리척척잘둘러대는능력 5.어떤사람을알아보는정도 6.약하게부는바람 8.성미가깔깔하고고집이세며모진사람 10.때때로여기저기흩어져발생하는 11.그시대에유행하는말 12.다섯개또는여섯개로보이는섬 13.죽은사람의남은가족 14.신념을굽히지않는의지 16.흘러가는시간 낱말퍼즐 *정답은아래에있습니다. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 김선생 수학 이번호 정답 스도쿠 이번호 정답 낱말퀴즈 이번호 정답 *문제는40p에있습니다. Solve the ffollowings (1-4) 1 4 − 3 = 3 4 − 2 − 1 ( 6, 7 학년 ) 2 2 3 + 2 = − 2 2 − 1 + 9 − 3 + 1 ( 7, 8 학년 ) 3 64 1 / 3 − 1 = 125 2 / 3 ( 8, 9 학년 ) 4 9 − 8 × 3 = − 2( − 3 + 2) − 5 ( 9, 10 학년 ) Simplify the followings (5-8) 5 2 25 + 4 400 + 7 81 − 10 196 ( 6, 7 학년 ) 6 2 9 − 5 4 − 3 16 ( 7, 8, 9 학년 ) 7 2 54 + 3 24 − 4 32 − 5 18 ( 8, 9 학년 ) 8 81 4 8 × 5 4 3 −2 ÷ 3 25 5 4 ( 9, 10 학년 ) (9) Smith divides the string of 15 cm into two parts. He finds that the square of the longer part is 4 times the square of the shorter one. What is the length of the longer one ? 김선생수학알제브라연습문제 (268) ( Exercise of Algebra ) ( Answer ) 1 4 − 3 = 3 4 − 2 − 1 4 − 3 = 3 × 2 − 1 4 = 8 ∴ = 2 2 2 3 + 2 = − 2 2 − 1 + 9 − 3 + 1 6 + 4 = − 4 + 2 + 9 − 2 6 + 4 = − 4 + 2 − 18 6 + 4 = − 16 − 4 10 = − 20 ∴ = − 2 3 64 1 / 3 − 1 = 125 2 / 3 [ 4 3 1 3 − 1] = (5 3 ) 2 / 3 4 − 1 = 5 2 3 = 25 ∴ = 25/3 4 9 − 8 × 3 = − 2( − 3 + 2) − 5 (3 ) 2 − 8 × 3 = 2 × 3 − 4 − 5 (3 ) 2 − 10 × 3 + 9 = 0 3 − 9 (3 − 1) = 0 3 = 9 , 3 = 1 ∴ = 0 , 2 5 2 25 + 4 400 + 7 81 − 10 196 = 2 × 5 + 4 × 20 + 7 × 9 − 10 × 14 = 10 + 80 + 63 − 140 = 13 6 2 9 − 5 4 − 3 16 = 2 × 9 − 5 × 4 − 3 × 16 = 2 × 3 − 5 × 2 − 3 × 4 = 6 − 10 − 12 = − 16 7 2 54 + 3 24 − 4 32 − 5 18 = 2 × 9 × 6 + 3 × 4 × 6 − 4 × 16 × 2 − 5 × 9 × 2 = 2 × 3 × 6 + 3 × 2 × 6 − 4 × 4 × 2 − 5 × 3 × 2 = 6 6 + 6 6 − 16 2 − 15 2 = 12 6 − 31 2 8 81 4 8 × 5 4 3 −2 ÷ 3 25 5 4 = 81 × 5 4 ÷ 3 25 4 8 × 3 −2 ÷ 5 ÷ 4 = 9 × 5 × 2 ÷ 3 ÷ 5 4+3−5 8−2−4 = 6 2 2 = 6 (9) Let x = length of longer one , then length of shorter one = 15 – x . x 2 = 4 (x − 15) 2 ( square of longer is 4 times the square of shorter ) x 2 = 4 x 2 − 120 x + 900 ( expand ) x 2 − 40x + 300 = 0 ( simplify ) ( x – 30 ) ( x – 10) = 0 x = 10 or 30 ( factorise and solve ) x = 10 ( length must be smaller than 15 cm of the length of the string ) Solve the followings (1-4) 1 4 − 3 = 3 4 − 2 − 1 ( 6, 7 학년 ) 2 2 3 + 2 = − 2 2 − 1 + 9 − 3 + 1 ( 7, 8 학년 ) 3 64 1 / 3 − 1 = 125 2 / 3 ( 8, 9 학년 ) 4 9 − 8 × 3 = − 2( − 3 + 2) − 5 ( 9, 10 학년 ) Simplify the followings (5-8) 5 2 25 + 4 400 + 7 81 − 10 196 ( 6, 7 학년 ) 6 2 9 − 5 4 − 3 16 ( 7, 8, 9 학년 ) 7 2 54 + 3 24 − 4 32 − 5 18 ( 8, 9 학년 ) 8 81 4 8 × 5 4 3 −2 ÷ 3 25 5 4 ( 9, 10 학년 ) (9) Smith divides the string of 15 cm into two parts. He finds that the square of the longer part is 4 times the square of the shorter one. What is the length of the longer one ? 김선생수학알제브라연습문제 (268) ( Exercise of Algebra ) ( Answer ) 1 4 − 3 = 3 4 − 2 − 1 4 − 3 = 3 × 2 − 1 4 = 8 ∴ = 2 2 2 3 + 2 = − 2 2 − 1 + 9 − 3 + 1 6 + 4 = − 4 + 2 + 9 − 2 6 + 4 = − 4 + 2 − 18 6 + 4 = − 16 − 4 10 = − 20 ∴ = − 2 3 64 1 / 3 − 1 = 125 2 / 3 [ 4 3 1 3 − 1] = (5 3 ) 2 / 3 4 − 1 = 5 2 3 = 25 ∴ = 25/3 4 9 − 8 × 3 = − 2( − 3 + 2) − 5 (3 ) 2 − 8 × 3 = 2 × 3 − 4 − 5 (3 ) 2 − 10 × 3 + 9 = 0 3 − 9 (3 − 1) = 0 3 = 9 , 3 = 1 ∴ = 0 , 2 5 2 25 + 4 400 + 7 81 − 10 196 = 2 × 5 + 4 × 20 + 7 × 9 − 10 × 14 = 10 + 80 + 63 − 140 = 13 6 2 9 − 5 4 − 3 16 = 2 × 9 − 5 × 4 − 3 × 16 = 2 × 3 − 5 × 2 − 3 × 4 = 6 − 10 − 12 = − 16 7 2 54 + 3 24 − 4 32 − 5 18 = 2 × 9 × + 3 × 4 × 6 − 4 × 16 × 2 − 5 × 9 × 2 = 2 × 3 × 6 + 3 × 2 × 6 − 4 × 4 × 2 − 5 × 3 × 2 = 6 6 + 6 6 − 16 2 − 15 2 = 12 6 − 31 2 8 81 4 8 × 5 4 3 −2 ÷ 3 25 5 4 = 81 × 5 4 ÷ 3 25 4 8 × 3 −2 ÷ 5 ÷ 4 = 9 × 5 × 2 ÷ 3 ÷ 5 4+3−5 8−2−4 = 6 2 2 = 6 (9) Let x = length of longer one , then length of shorter one = 15 – x . x 2 = 4 (x − 15) 2 ( square of longer is 4 times the square of shorter ) x 2 = 4 x 2 − 120 x + 900 ( expand ) x 2 − 40x + 300 = 0 ( simplify ) ( x – 30 ) ( x – 10) = 0  x = 10 or 30 ( factorise and solve ) x = 10 ( length must be smaller than 15 cm of the length of the string ) The length of the longer one is 10 cm. Solve the followings (1-4) 1 4 − 3 = 3 4 − 2 − 1 ( 6, 7 학년 ) 2 2 3 + 2 = − 2 2 − 1 + 9 − 3 + 1 ( 7, 3 64 1 / 3 − 1 = 125 2 / 3 ( 8, 9 학년 ) 4 9 − 8 × 3 = − 2( − 3 + 2) − 5 ( 9, 10 Simplify the followings (5-8) 5 2 25 + 4 400 + 7 81 − 10 196 ( 6, 7 학 6 2 9 − 5 4 − 3 16 ( 7, 8, 9 학년 7 2 54 + 3 24 − 4 32 − 5 18 ( 8, 9 학년 8 81 4 8 × 5 4 3 −2 ÷ 3 25 5 4 ( 9, 1 (9) Smith divides the string of 15 cm into two parts. He finds that the square of the longer part is 4 times the squ What is the length of the longer one ? 김선생수학알제브라연습문제 (268) ( Exerc ( Answer ) 1 4 − 3 = 3 4 − 2 − 1 4 − 3 = 3 × 2 − 1 4 = 8 ∴ = 2 2 2 3 + 2 = − 2 2 − 1 + 9 − 3 + 1 6 + 4 = − 4 + 2 + 9 − 2 6 + 4 = − 4 + 2 − 18 6 + 4 = − 16 − 4 10 = − 20 ∴ = − 2 3 64 1 / 3 − 1 = 125 2 / 3 [ 4 3 1 3 − 1] = (5 3 ) 2 / 3 4 − 1 = 5 2 3 = 25 ∴ = 25/3 4 9 − 8 × 3 = − 2( − 3 + 2) − 5 (3 ) 2 − 8 × 3 = 2 × 3 − 4 − 5 (3 ) 2 − 10 × 3 + 9 = 0 3 − 9 (3 − 1) = 0 3 = 9 , 3 = 1 ∴ = 0 , 2 5 2 25 + 4 400 + 7 81 − 10 196 = 2 × 5 + 4 × 20 + 7 × 9 − 10 × 14 = 10 + 80 + 63 − 140 = 13 6 2 9 − 5 4 − 3 16 = 2 × 9 − 5 × 4 − 3 × 16 = 2 × 3 − 5 × 2 − 3 × 4 = 6 − 10 − 12 = − 16 7 2 54 + 3 24 − 4 32 − 5 18 = 2 × 9 × 6 + 3 × 4 × 6 − 4 × 16 × 2 − 5 × 9 × = 2 × 3 × 6 + 3 × 2 × 6 − 4 × 4 × 2 − 5 × 3 × 2 = 6 6 + 6 6 − 16 2 − 15 2 = 12 6 − 31 2 8 81 4 8 × 5 4 3 −2 ÷ 3 25 5 4 = 81 × 5 4 ÷ 3 25 4 8 × 3 −2 ÷ 5 ÷ 4 = 9 × 5 × 2 ÷ 3 ÷ 5 4+3−5 8−2−4 = 6 2 2 = 6 (9) Let x = length of longer one , then length of shorter one x 2 = 4 (x − 15) 2 ( square of longer is 4 times the squar x 2 = 4 x 2 − 120 x + 900 ( expand ) x 2 − 40x + 300 = 0 ( simplify ) ( x – 30 ) ( x – 10) = 0  x = 10 or 30 ( factorise and s x = 10 ( length must be smaller than 15 cm of the length The length of the longer one is 10 cm.